35=g^2-19g+85

Solution for 35=g^2-19g+85 equation:

35=g^2-19g+85

We move all terms to the left:

35-(g^2-19g+85)=0

We get rid of parentheses

-g^2+19g-85+35=0

We add all the numbers together, and all the variables

-1g^2+19g-50=0

a = -1; b = 19; c = -50;
Δ = b2-4ac
Δ = 192-4·(-1)·(-50)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{161}}{2*-1}=\frac{-19-\sqrt{161}}{-2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{161}}{2*-1}=\frac{-19+\sqrt{161}}{-2}
$